The solubility products $(K_{sp})$ of three sparingly soluble salts $M_2X$,$MX$,and $MX_3$ are identical. What will be the order of their solubilities $(s)$?

Given that the solubility product constants $(K_{sp})$ follow the order $K_{sp}(Mg(OH)_2) > K_{sp}(Zn(OH)_2) > K_{sp}(Fe(OH)_3)$,what is the order of precipitation of these hydroxides?

The solubility of calcium carbonate $(CaCO_3)$ at $298 \ K$ is $6.4 \times 10^{-5} \ mol \ dm^{-3}$. Calculate the value of solubility product $(K_{sp})$ at the same temperature.

If $S$ and $K_{sp}$ are respectively solubility and solubility product of a sparingly soluble binary electrolyte,then

In an aqueous solution,$SCN^-$,$Br^-$,$I^-$,and $Cl^-$ are present. Which will get precipitated first when $AgNO_3$ is added to the solution? Given that:
$K_{sp}(AgCl) = 1.2 \times 10^{-10}$,
$K_{sp}(AgI) = 1.7 \times 10^{-16}$,
$K_{sp}(AgSCN) = 7.1 \times 10^{-7}$,
$K_{sp}(AgBr) = 3.5 \times 10^{-13}$

The solubility product of $Mg(OH)_2$ is $1.0 \times 10^{-12}$. Concentrated aqueous $NaOH$ solution is added to a $0.01 \ M$ aqueous solution of $MgCl_2$. The $pH$ at which precipitation occurs is